How many atoms of oxygen are represented in 2Al2(CO3)3? 6 9 3 18
\(2AL_2(CO_3)_3\)
Just look at the number of each element present.
So it appears that without the two coefficients, you have 2 Al, 3 C, and 6 O
18?
But with the coefficient of two, you would take that amount and multiply by 2
or wait!
haha, how many molecules of oxygen. Whoops
9+4=12 and thats not an option
@rebeccaxhawaii is this a compound?
yes
Well...if Oxygen occurs diatomically, then i suppose 6 would make sense
6 would make the most sense here.
oh wait. I see. It has three carbonate ions that each have three oxygen atoms, so that makes a total of 9 oxygen atoms per aluminum carbonate. You have two aluminum carbonate compounds, so you have a grand total of 18 oxygen atoms
That makes sense
The answer should be D
alright so i was right?
ye
thank you
If this is a compound, then the 2 coefficient applies to the oxygen. there is 9 present without the coefficient. So 9 x 2 = 18
np. My apologies for the initial confusion, probably should have read more carefully
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