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Mathematics 21 Online
rebeccaxhawaii (rebeccaxhawaii):

How many atoms of oxygen are represented in 2Al2(CO3)3? 6 9 3 18

HanAkoSolo (jamierox4ev3r):

\(2AL_2(CO_3)_3\)

HanAkoSolo (jamierox4ev3r):

Just look at the number of each element present.

HanAkoSolo (jamierox4ev3r):

So it appears that without the two coefficients, you have 2 Al, 3 C, and 6 O

rebeccaxhawaii (rebeccaxhawaii):

18?

HanAkoSolo (jamierox4ev3r):

But with the coefficient of two, you would take that amount and multiply by 2

HanAkoSolo (jamierox4ev3r):

or wait!

HanAkoSolo (jamierox4ev3r):

haha, how many molecules of oxygen. Whoops

rebeccaxhawaii (rebeccaxhawaii):

9+4=12 and thats not an option

HanAkoSolo (jamierox4ev3r):

@rebeccaxhawaii is this a compound?

rebeccaxhawaii (rebeccaxhawaii):

yes

HanAkoSolo (jamierox4ev3r):

Well...if Oxygen occurs diatomically, then i suppose 6 would make sense

HanAkoSolo (jamierox4ev3r):

6 would make the most sense here.

HanAkoSolo (jamierox4ev3r):

oh wait. I see. It has three carbonate ions that each have three oxygen atoms, so that makes a total of 9 oxygen atoms per aluminum carbonate. You have two aluminum carbonate compounds, so you have a grand total of 18 oxygen atoms

HanAkoSolo (jamierox4ev3r):

That makes sense

HanAkoSolo (jamierox4ev3r):

The answer should be D

rebeccaxhawaii (rebeccaxhawaii):

alright so i was right?

HanAkoSolo (jamierox4ev3r):

ye

rebeccaxhawaii (rebeccaxhawaii):

thank you

HanAkoSolo (jamierox4ev3r):

If this is a compound, then the 2 coefficient applies to the oxygen. there is 9 present without the coefficient. So 9 x 2 = 18

HanAkoSolo (jamierox4ev3r):

np. My apologies for the initial confusion, probably should have read more carefully

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