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Mathematics 18 Online
rebeccaxhawaii (rebeccaxhawaii):

Write out the balanced equation for the reaction that occurs when Mg(OH)2 and HCl react together. You do not need to make your subscripts smaller; just write them out as regular numbers. For example: Mg(OH)2. @vocaloid

HanAkoSolo (jamierox4ev3r):

This should probably be posted in chemistry...but regardless, just know that for the future

HanAkoSolo (jamierox4ev3r):

Anyhow, you want to identify what type of a reaction this is first, so you can identify how the reactants need to be rearranged to form the products

rebeccaxhawaii (rebeccaxhawaii):

no one is in chem rn

HanAkoSolo (jamierox4ev3r):

From the looks of it, we appear to be dealing with a double-replacement reaction between \(Mg(OH)_2\) and HCl.

HanAkoSolo (jamierox4ev3r):

lol, I always check the chem. section. Personally

OpenStudy (triciaal):

remember acid + base = salt + water then balance the molecules on each side

HanAkoSolo (jamierox4ev3r):

but yeah, back to the question. If we have a double-replacement reaction, H will probably form a compound with the OH from the MgOH_2 compound, and Mg will form a compound with Cl.

HanAkoSolo (jamierox4ev3r):

So based from this, what do you think the products will be? @rebeccaxhawaii

HanAkoSolo (jamierox4ev3r):

Mg(OH)2 is an base. while HCl is definitely an acid. ^ To clarify

rebeccaxhawaii (rebeccaxhawaii):

MgCl2 + 2H2O?

HanAkoSolo (jamierox4ev3r):

Good!

HanAkoSolo (jamierox4ev3r):

Although, I'm not sure why you added a coefficient to water at this point, lol

HanAkoSolo (jamierox4ev3r):

Butt yeah, if our equation was unbalanced, it would look like this at this point: HCl + MG(OH)2 = H2O + MGCl2

rebeccaxhawaii (rebeccaxhawaii):

so its just H2O + MGCl2?

HanAkoSolo (jamierox4ev3r):

This is unbalanced. We need to make sure we balance it

rebeccaxhawaii (rebeccaxhawaii):

and how would that happen

HanAkoSolo (jamierox4ev3r):

HCl + MG(OH)2 = H2O + MGCl2 Reactants: Products: *3 H *2 H *1 Cl *1 O *1 Mg *1 Mg *2 O *2 Cl

HanAkoSolo (jamierox4ev3r):

so if there are these many things on each side, how can we balance it in order to get them even?

HanAkoSolo (jamierox4ev3r):

hint! The key probably falls upon looking at the Hydrogens and Chlorine

HanAkoSolo (jamierox4ev3r):

@rebeccaxhawaii any ideas?

rebeccaxhawaii (rebeccaxhawaii):

this part always confuses me

HanAkoSolo (jamierox4ev3r):

So let's see what happens if we add a subscript to HCl in the reactants: 2HCl + MG(OH)2 = H2O + MGCl2 Reactants: Products: *4 H *2 H *2 Cl *1 O *1 Mg *1 Mg *2 O *2 Cl See how the amount of Cl in the reactants/products is now the same? We're one step away from being balanced Note how there is 4 H and 2 O in the reactants, and 2 H and 1 O in the products. Therefore, what is the last subscript and where should it go? @rebeccaxhawaii

rebeccaxhawaii (rebeccaxhawaii):

doubling it

rebeccaxhawaii (rebeccaxhawaii):

H2O + 2MGCl2?

HanAkoSolo (jamierox4ev3r):

Ah, not quite! We already have the correct amount of Mg and Cl.

HanAkoSolo (jamierox4ev3r):

Do you see how there is only 1 O and 2 H in the reactants? we want it to become 2 O and 4 H, just like the reactants. So the 2 coefficient should go in front of H2O. Does that make sense?

rebeccaxhawaii (rebeccaxhawaii):

2H2O + MGCl2?

HanAkoSolo (jamierox4ev3r):

yup!

HanAkoSolo (jamierox4ev3r):

2HCl + MG(OH)2 = 2H2O + MGCl2 Reactants: Products: *4 H *4 H *2 O *2 O *1 Mg *1 Mg *2 Cl *2 Cl

HanAkoSolo (jamierox4ev3r):

Do you see how everything matches? You want to make sure that there is the same amount of reactant and product. Does this make sense? @rebeccaxhawaii

rebeccaxhawaii (rebeccaxhawaii):

YAY THANK YOU. can you help with one more?

HanAkoSolo (jamierox4ev3r):

Unfortunately, I have to go to class right now :/ But if your question is not answered by the time I'm done, I will gladly help you :)

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