Solve for n
\[\log_{9}27=n \]
n is already isolated. Did you mean simplify?
probably means find the value of \(n\) that makes this true...
\[\log_b a =n \] means the number \(n\) is the power you have to raise \(b\) to in order to get \(a\) so for example \[\log_{10} 1000 = 3\]because \[10^3=1000\]
hint: this problem will involve a fractional power, so it may be helpful to remember that \[n^{a/b} = \sqrt[b]{n^a}\]
This simply means 9^n = 27 (3^2)^n = 27 = 3^3 so 3^2n = 3^3 and 2n = 3 giving n = 3/2 Or you can maintain the log but change the term within as follows... \[\log_9 27 = \log_9 3^3 = 3 \log_9 3 = 3 \log_9 \sqrt{9} = 3 \log_9 (9)^{0.5} = \frac{ 3 }{ 2 } \log_9 9 = \frac{ 3 }{ 2 }\]
An alternative approach is to change the base to a nicer one, say base 3 rather than base 9 and this gives the answer very directly! Use this change base rule: \[\log_ab= \frac{ \log_cb }{ \log_ca }\] So \[\log_927 = \frac{ \log_3 27 }{ \log_39 }=\frac{ 3 }{ 2 }\]
please close this question if your finished getting help
also, if you are allowed to use a calculator, you can do \[ \log_9 27= \frac{\log 27}{\log 9 } \] where log means log base 10 (the one your calculator uses)
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