Write an equation in point-slope form of the line that passes through the given points, then write the equation in slope-intercept form. (−9,7), (9,1) What is the point-slope form of the equation of the line?
First find the slope... \(\huge\bf{\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \rightarrow \frac{11-7}{9+9}=slope}\)
Well I already did that eith the rise and run but idk how to make an equation
@563blackghost
6/18 = 1/3 Can you look over the question again
We are already given the first points which is `(-9,7)` we would input it here.... \(\huge\bf{y-y_{1}=m(x-x_{1})}\) We input the point in as \(\large\bf{(x_{1},y_{1})}\). \(\huge\bf{y+9=m(x-7)}\) If we simplify the slope we get \(\large\bf{\frac{2}{9}}\). We input this as m. \(\huge\bf{y+9=\frac{2}{9}(x-7)}\) This is how it would look.
oh it says it's wrong though
Wait so it was 1 not 11?
yes
Ok so thats why its wrong. So we have to find the slope again. \(\huge\bf{\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \rightarrow \frac{1-7}{9+9}=-\frac{1}{3}}\) With this we would input to find the y-intercept by inputting point. \(\huge\bf{7=-\frac{1}{3}(-9)+b}\) Simplify. \(\huge\bf{7=3+b}\) \(\huge\bf{4=b}\) \(\huge\bf\color{red}{y=-\frac{1}{3}x+b}\)
Sorry forgot to input... \(\huge\bf\color{red}{y=-\frac{1}{3}x+4}\)
what about slope intercept on the equation on theline??
Sorry that was for the slope-intercept. The point slope is this... \(\huge\bf\color{red}{y-7=-\frac{1}{3}(x+9)}\) So so sorry.
The point is `(7,-9)` we input into the equation as `(x1,y2)`
oh lol that's why I got it arong again lol
Im so sorry
It'll be fine but what was the answer for slope-inter?
\(\huge\bf\color{red}{y=-\frac{1}{3}x+4}\)
I hope they are correct :) I must take my leave, good luck with your work ^.^
thanks!
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