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Mathematics 7 Online
OpenStudy (blazeryder):

What is the inverse of this function? Will write the function below.

OpenStudy (blazeryder):

\[y=\log _{4}x\]

Vocaloid (vocaloid):

start by swapping x and y

Vocaloid (vocaloid):

\[x = \log_{4} y\]

Vocaloid (vocaloid):

any ideas how to get rid of that "log4"?

OpenStudy (blazeryder):

Sorry, I don't......

Vocaloid (vocaloid):

we can re-write both sides in base 4

Vocaloid (vocaloid):

\[4^x = 4^{\log_{4}y}\]

OpenStudy (blazeryder):

What would you do next? I am totally lost!

Vocaloid (vocaloid):

the "4log4" cancels out

OpenStudy (blazeryder):

This is my first time dealing with logs

Vocaloid (vocaloid):

so you get \[4^{x} = y\]

OpenStudy (blazeryder):

Ahh, that makes sense! So first you swap the x and y. Then you you write the base of whatever the b is. And then the \[b ^{\log _{b}}\]cancels each other out. And then you get your answer. Am I right?

Vocaloid (vocaloid):

yup! good job!

OpenStudy (blazeryder):

Awesome! Thank you very much! My Algebra 2 book does not tell me how to do this so thought I would ask! =) Again, thank you!

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