Question

Can someone do this for me please I am in such need of finishing this immeditaly i do not care if you get me a 2% I just want it done

Answer 1

@triciaal @3mar

Answer 2

Well, I am here.
Could you give me just 2 min?

Answer 3

Well, I am here.
What do you think?
Any ideas?

Answer 4

Sure take your time

Answer 5

no idea at all

Answer 6

\[q=m C_p \Delta T\]

Answer 7

equation for calculating the total amount of heat required in order to increase the temperature of a material

Answer 8

If all heat from the sample A is transferred to the 240 g of water, so the equation of @sooobored works.

q is the total heat transferred.
m is the mass of water
\(C_p\) is the specific heat of water (4.2 kj/kg.K)
ΔT is the temperature difference of water due to the heat transferrred

Answer 9

@sparklestaraa

Do you follow?

Answer 10

So if you want to calculate:
just substitute with:

m=240 gm =0.24 kg,
C_p=4.2 kj/kg.K
ΔT=77 degree

So it would be"
\[\large q=m.C_p.\Delta T=(0.24~kg)*(4.2~kJ/kg.K)*(77~C~degree)\\\Large \color{Teal }{q=77.616~kJ}\]


Now we need to convert this from \(kJ\) to\( Calories\)