Question

HELP ASAP PLEAS

Answer 1

@3mar

Answer 2

What is that?

Answer 3

Your expression looks like this.

((x2-2)x)/x3+3

It is not possible to make any siginificant improvement on the numeration or denominator.

You should get something like

dy/dx=(-6+9 x^2+4 x^3)/(3+x^3)^2

as your answer using the quotient rule and then the chain rule and power rule.

Answer 4

@DoodleDuck8 wow! thank you- so it would be C right??

Answer 5

Which one is C

Answer 6

what was the answer that you were thinking?? @DoodleDuck8

Answer 7

Yes, I think it is C

Answer 8

really? are you a 100% sure? :-) @DoodleDuck8

Answer 9

Yes :)

Answer 10

ok- may i ask you a few more please?? you really help alot!

Answer 11

please:-)

Answer 12

Ok

Answer 13

Sorry figuring it out

Answer 14

its fine thankyou

Answer 15

take the derivative of f(g(x)). just treat them like they are variables. so you get:

h'=f'(g(x))g'(x)

now plug in your x value and evaluate:

h'(1)=f'(g(1))(g'(1))

substitute in values that you know and evaluate again

h'(1)=f'(3)(-3)
h'(1)=(-5)(-3)=15

Answer 16

Remember the chain rule.
L(x)=f(g(x))
L'(x)=f'(g(x))g'(x)

Answer 17

so ti would be A:??? @DoodleDuck8

Answer 18

please dont leave i have just 2 more wustions please :-)

Answer 19

Yes A, I will stay

Answer 20

Suppose f and g are differentiable functions and that (f g) (x)= x^2/x-1, f(4)=2 and f'(4)=3/4 Determine the following a) g(4) and b) g'(4)

Answer 21

No problem

Answer 22

there are no multiple choices for this one sorry what do you think it wil be?

Answer 23

The function f(x) = (x3 + 2x + 3)(3x3 - 6x2 - 8x + 1).
Simplify f(x).
f(x) = (x3 + 2x + 3)(3x3 - 6x2 - 8x + 1)
= 3x6 + 6x4 + 9x3 - 6x5 - 12x3 - 18x2 - 8x4 - 16x2 - 24x + x3 + 2x + 3
= 3x6 - 6x5 - 2x4 - 2x3 - 34x2 - 22x + 3
⇒ f(x) = 3x6 - 6x5 - 2x4 - 2x3 - 34x2 - 22x + 3.
Differentiate the function with resprct to x.
f '(x) = [3x6 - 6x5 - 2x4 - 2x3 - 34x2 - 22x + 3]'
f '(x) = 3(x6)' - 6(x5)' - 2(x4)' - 2(x3)' - 34(x2)' - 22x' + 3'
Derivative of xn = nx(n - 1) and derivative of constant is zero.
f '(x) = 3(6x5) - 6(5x4) - 2(4x3) - 2(3x2) - 34(2x) - 22(1) + 0
f '(x) = 18x5 - 30x4 - 8x3 - 6x2 - 68x - 22.
Again differentiate the above equation with respect to x.
f ''(x) = [18x5 - 30x4 - 8x3 - 6x2 - 68x - 22]'
f ''(x) = 18(x5)' - 30(x4)' - 8(x3)' - 6(x2)' - 68x' - 22'
f ''(x) = 18(5x5) - 30(4x3) - 8(3x2) - 6(2x) - 68(1) - 0
f ''(x) = 90x5 - 120x3 - 24x2 - 12x - 68.
Therefore, coefficient of the squared term(i.e, coefficient of x2) of f ''(x) is - 24.

Answer 24

Answer : -24

Answer 25

i agree! thats what i got!!! Now finally last one??: Find f '(−4), if f(x) = (5x2 + 6x)(3x2 + 7). Round your answer to the nearest integer. Use the hyphen symbol, -, for negative values.

Answer 26

That's great

Answer 27

f'(x) = (10x+6)*(3x^2+7) + (5x^2 + 6x)*(6x)
f'(-4) = (-40+6)*(48+7) + (80-24)*(-24)
= -34*55 + 56*(-24)
= -3214

Answer 28

That is correct.

Answer 29

thank you! and for the second to last question where the answr you said and the answer i got (-24) that was wrong.... can we try it again?

Answer 30

@DoodleDuck8

Answer 31

Ok, sorry

Answer 32

The function looks like (u.v), so its derivative looks like: (u'.v) + (v'.u) → where:

u = x³ + 2x + 3 → u' = 3x² + 2

v = 3x³ - 6x² - 8x + 1 → v' = 9x² - 12x - 8


f'(x) = (u'.v) + (v'.u)

f'(x) = [(3x² + 2)(3x³ - 6x² - 8x + 1)] + [(9x² - 12x - 8)(x³ + 2x + 3)]

f'(x) = [9x^5 - 18x^4 - 24x³ + 3x² + 6x³ - 12x² - 16x + 2] + [9x^5 + 18x³ + 27x² - 12x^4 - 24x² - 36x - 8x³ - 16x - 24]

f'(x) = 9x^5 - 18x^4 - 24x³ + 3x² + 6x³ - 12x² - 16x + 2 + 9x^5 + 18x³ + 27x² - 12x^4 - 24x² - 36x - 8x³ - 16x - 24

f'(x) = 18x^5 - 30x^4 - 8x³ - 6x² - 68x - 22

f''(x) = 90x^4 - 120x³ - 24x² - 12x - 68

Answer 33

Bye, hope this helped