Question

HELP

Answer 1

Find the derivative dy, dx for y equals the quotient of the quantity x cubed minus 5 times x and the quantity x squared minus 1..
dy dx equals the quotient of the quantity x squared minus 1 times the quantity 3 times x squared minus 5 minus the product of x cubed minus 5 times x and 2x, and the square of the quantity x squared minus.
dy dx equals the quotient of the quantity x cubed minus 5 times x times the quantity 2x minus the product of the quantity x squared minus 1 times the quantity 3 times x squared minus 5, and the square of the quantity x squared minus.
dy dx equals the quotient of the quantity x squared minus 1 times the quantity 3 times x squared minus 5 plus the product of x cubed minus 5 times x and 2x, and the square of the quantity x squared minus.
dy dx equals the quotient of the quantity 3 times x squared minus 5, and 2 times x.

Answer 2

@steve816 i keeo getting option C but it is wrong sorry

Answer 3

yes sorry will do please help with this one in mean time!

Answer 4

Okay

Answer 5

ok i medaled now this one if you can

Answer 6

Is this the actual question? Why is it in all words? lol

Answer 7

@steve816 yes/// i know im so sorry im hoping you can still help with it :-(

Answer 8

can you? it is not C that is for srure

Answer 9

You should be able to figure this out from the quotient rule

Answer 10

Lemme check

Answer 11

Sorry, I gotta go!

Answer 12

no please i really needed hekp with

Answer 13

Is this the question: What is \(\dfrac{dy}{dx}\), for \(y = \dfrac{x^3 - 5x}{x^2 - 1}\) ?

A.
```
dy dx equals the quotient of
the quantity x squared minus 1 times the quantity 3 times x squared minus 5
minus the product of x cubed minus 5 times x and 2x,
and the square of the quantity x squared minus *1*.
```
\[\frac{(x^2-1)(3x^2-5) - (x^3-5x)(2x)}{x^2-1}\]

B.
```
dy dx equals the quotient of
the quantity x cubed minus 5 times x times the quantity 2x
minus the product of the quantity x squared
minus 1 times the quantity 3 times x squared minus 5,
and the square of the quantity x squared minus *1*.
```
\[\frac{(x^3-5x) (2x) - 1(3x^2 - 5))}{(x^2-1)}\]

C.
```
dy dx equals the quotient of the quantity x squared minus 1 times
the quantity 3 times x squared minus 5
plus the product of x cubed minus 5 times x and 2x,
and the square of the quantity x squared minus *1*.
```
\[\frac{(x^2-1)(3x^2-5) + (x^3-5x)(2x)}{(x^2 - 1)}\]


D.
```
dy dx equals the quotient of the quantity 3 times x squared minus 5, and 2 times x.
```
\[\frac{3x^2-5}{2x}\]

Answer 14

(EDIT:)
A. \[\frac{(x^2-1)(3x^2-5) - (x^3-5x)(2x)}{(x^2-1)^2}\]
B. \[\frac{(x^3-5x) (2x) - 1(3x^2 - 5))}{(x^2-1)^2}\]
C. \[\frac{(x^2-1)(3x^2-5) + (x^3-5x)(2x)}{(x^2 - 1)^2}\]
D. \[\frac{3x^2-5}{2x}\]

Answer 15

The formula is: \(\left( \frac{f(x)}{g(x)}\right)' = \frac{g(x)f'(x) - f(x)g'(x)}{g(x)^2}\).

\[\frac{(\cdots)(\cdots)' - (\cdots)(\cdots)'}{(x^2-1)^2}\]
Apply the formula carefully.