Question

P=?
3p/6p+7=39
I think it's 8. Anyone agree?

Answer 1

\(\color{black}{\displaystyle \frac{3p}{6p+7}=39 }\) or \(\color{black}{\displaystyle \frac{3p}{6p}+7=39 }\)

Answer 2

first one

Answer 3

I know the process on how to figure it out just need an aproval :)

Answer 4

\(\color{black}{\displaystyle \frac{3p}{6p+7}=39 }\)

\(\color{black}{\displaystyle \frac{3p}{6p+7}(6p+7)=39(6p+7) }\)

Answer 5

multiply on both sides times the quantity in the denominator, so that you can get rid of the fraction, first.

Answer 6

Can you simplify and expand on both sides?

Answer 7

well it's not exactly a fraction it's dividing

Answer 8

we will have to subtract 7 from 39 and 6p+7 and get 6p=32

Answer 9

6 divided into 6p is p and 32 ÷ 6 = 5.3

Answer 10

Once you have found a value of p, please check your answer yourself by substituting it into the original equation. Is that equation now true? If so, your "solution" is correct. Be really careful with those parentheses; they are not optional (unless you want confused helpers).

Answer 11

if we replace 8 into the equation we get :
3•8=24
________
6 •8=48+7=55


24/55

Answer 12

55 ÷ 24

Answer 13

You think p=8? Please subst. 8 for p in the original equation. Is that equation now true?

Answer 14

not sure

Answer 15

I'm very confused

Answer 16

Not sure about what? Confused about what? Please explain. Originally you wanted to know whether your solution, p=8, is correct; I am explaining how you can check it easily by yourself.

Answer 17

oh I see

Answer 18

\[\color{black}{\displaystyle \frac{3p}{6p+7}=39 }\]

Answer 19

\[3p/6p+7=39 \]

Answer 20

39-7=32

Answer 21

i have to go now sorry

Answer 22

Wait, please. Are you SURE you want 3p/6p+7 = 32? I don't agree, and neither does Solomon.

Answer 23

Come back when you have adequate time to finish this.

Answer 24

I will schedule a get together you could continue putting explanations in here

Answer 25

ok thats fine

Answer 26

get togthere with my teacher

Answer 27

No. As a matter of principle I want to work with you while you're here and participating.

Answer 28

ok

Answer 29

Here's a similar example. Let's say we had the equation \(\Large x+2 = 6\) and I claim that \(\Large x = 8\) is the solution

How can I test this claim? By following what @mathmale is suggesting. Replace every copy of x with 8 and see if you get a true equation. Let's do that

\[\Large x+2 = 6\]

\[\Large {\color{red}{x}}+2 = 6\]

\[\Large {\color{red}{8}}+2 = 6\]

\[\Large 10 = 6\]

The last equation is false, so `x+2=6` is false when x = 8. Therefore, x = 8 is NOT the solution here.