Question

Assuming x and y are positive,use properties of logarithms to write the expression as a sum or difference of a logarithm or multiples of logarithms. In cubed(x)/cubed(y)?

Answer 1

@jim_thompson5910

Answer 2

@zepdrix

Answer 3

@mathmale

Answer 4

do you think it hence

ln x^3 /y^3 = ?

Answer 5

cubed root

Answer 6

do you know this property of logarithms

log a -log b = log (a/b)

log a^x = xlog a

log a +log b = log a*b

Answer 7

yep

Answer 8

ok. so than just use the necessary

Answer 9

do you mean cuberoot of x divide cuberoot y ?

Answer 10

so the quoitent rule

Answer 11

yes

Answer 12

\[\ln \sqrt[3]x / \sqrt[3]{y} =\]

Answer 13

in this way ?

Answer 14

inx/3-iny/3

Answer 15

hence ?

just ln x/3 -ln y/3 = ?

Answer 16

cubed x dont mean x^3 ?

Answer 17

just bc. you wrote in the text of your exercise cubed x and cubed y

Answer 18

ok so is it 1/3(in x- In y)

Answer 19

this is just than you wan saying that your exercise is

ln x^(1/3) -ln y^(1/3) what is equal ln (cuberoot x / cuberoot y )

Answer 20

3

Answer 21

what mean this 3 ?

Answer 22

i dont know what your are asking

Answer 23

please clarify how is this your exercise correct ?

Answer 24

please make a copy past

Answer 25

when you use the quotient rule your trying to subtract

Answer 26

so ration cube root (x)= 1/3

Answer 27

so 1/3(In x- In y)

Answer 28

do you think

ln a^x = xln a

ln a^x -ln b^x = xln (a/b)

Answer 29

ok. ?

Answer 30

cuberoot x = x^(1/3)

Answer 31

do you think it so ?

Answer 32

yes

Answer 33

thats what my teacher taught us is the wayy i am solving it

Answer 34

so in this case there are

ln (cuberoot x / cuberoot y ) =

ln [x^(1/3) / y^(1/3) ] =

ln ( x/y)^(1/3) =

(1/3)ln x/y

do you think it hence ?

Answer 35

you are confusing me. where is the subtraction.

Answer 36

= (1/3)(ln x -ln y) =

= (1/3)ln x/y

Answer 37

bc. this is a propertie

log a -log b = log a/b

ok. ?

Answer 38

i will ask my teacher because i am confused.

Answer 39

ok

Answer 40

what is confusably for you ?

Answer 41

@mathmale please