What is the pH for a solution containing 1nM NaOH

Question

nottim · Answer

using $$pH=\log(kw/[OH])$$ I got -10

nottim · Answer

using $$pH=pkw+\log(cb)$$ I got 5

nottim · Answer

Answer is 7.

nottim · Answer

@sweetburger

nottim · Answer

Figrued out pkw=-logkw, stil lgot answer -10

helpppp · Answer

I keep trying to help, but I lose connection before it posts. But you have to understand that 1nM is a nano-molar. a nanomolar is equal to approximately 1.0000008054387, etc. That means your [OH-] is  1.0000008054387. to find the pOH, which you will need to find the pH, you do -log[OH-]. Once you do that you get 6.9999996502026. Round that up and you have 7. to find the pH, simply subtract 7 from kw or 14. 14-7=7

helpppp · Answer

Thank god, it posted

nottim · Answer

hate openstudy's interface so much for that

helpppp · Answer

It is rather annoying. XD I had typed that out like 5 different times before it finally posted