Question

write the equation of a line that is perpendicular to the given line that passes through the given point.

Answer 1

here is the equation

y-2=7/3(x+5);(-4,9)

Answer 2

\[\large y-2=\frac{ 7 }{ 3 }(x+5)\]

Do you know the slope of that given line?

Answer 3

no

Answer 4

remember the point slope form of a line..
y - y1 = m*(x - x1)

the slope of that line is m, and it goes through point (x1,y1)

Answer 5

A. y-9=-3/7(x-4)
B. y-9=3/7(x-4)
C. y-9=-3/7(x+4)
D. y-9=3/7(x+4)

Answer 6

these are the answer choices

Answer 7

The given line has the slope 7/3.
To get a slope perpendicular to that, you flip over the fraction and change the sign.

Answer 8

A perpendicular line will have a slope m=-3/7
and goes through given point (x1,y1)=(-4 , 9)

Answer 9

Point slope form of a line...

y - y1 = m*(x - x1)

sub in the values

Answer 10

is it A

Answer 11

almost, for the (x-x1) part though, it is minus a negative 4, turns into a plus 4.

y - 9 = -3/7 (x - (-4))

y - 9 = -3/7 (x + 4)

Answer 12

oh thanks