Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (yellowfellow007):

A tractor is pulling two logs in tandem. The logs are fastened together by a chain. Each log weighs 1800.0 N, and the logs are moving with a constant velocity. The tractor exerts a force of 1440 N on the front log, and this same log is acted on by a force of friction of 941 N.

OpenStudy (sooobored):

FREE BODY DIAGRAMSSSSS

OpenStudy (sooobored):

ok, constant velocity means that the net force on the object is equal to zero

OpenStudy (sooobored):

also, what is the question?

OpenStudy (s-mlipinsky):

1440-941?

OpenStudy (s-mlipinsky):

Wait no. The log doesn't move because it has too muvh mass and the tractor can't pull it

OpenStudy (s-mlipinsky):

If that's not correct try 1440-941-360 if you typed the logs' mass wrong

OpenStudy (s-mlipinsky):

Wait no. The log doesn't move because it has too muvh mass and the tractor can't pull it

OpenStudy (s-mlipinsky):

1440-941?

OpenStudy (yellowfellow007):

right i tried that 1440-941/ (3600/9.8) nothing good so far.

OpenStudy (yellowfellow007):

(a) Determine the tension (in Newtons) in the chain between the two logs.

OpenStudy (yellowfellow007):

(b) Determine the force of friction (in Newtons) on the back log.

OpenStudy (sooobored):

did you draw the FBD yet?

OpenStudy (yellowfellow007):

yeah its a nice beautiful thing|dw:1479711123867:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!