A tractor is pulling two logs in tandem. The logs are fastened together by a chain. Each log weighs 1800.0 N, and the logs are moving with a constant velocity. The tractor exerts a force of 1440 N on the front log, and this same log is acted on by a force of friction of 941 N.
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ok, constant velocity means that the net force on the object is equal to zero
also, what is the question?
1440-941?
Wait no. The log doesn't move because it has too muvh mass and the tractor can't pull it
If that's not correct try 1440-941-360 if you typed the logs' mass wrong
Wait no. The log doesn't move because it has too muvh mass and the tractor can't pull it
1440-941?
right i tried that 1440-941/ (3600/9.8) nothing good so far.
(a) Determine the tension (in Newtons) in the chain between the two logs.
(b) Determine the force of friction (in Newtons) on the back log.
did you draw the FBD yet?
yeah its a nice beautiful thing|dw:1479711123867:dw|
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