Question

Help with easy functions

Answer 1

what ye need help with?

Answer 2

Could I help you?

Answer 3

3mar might need to help you on this one sorry.. <:)

Answer 4

yes @3mar

Answer 5

Pleasure is mine!

Answer 6

=)

Answer 7

1 min

Answer 8

ok

Answer 9

Are you familiar with what the function means?

Answer 10

No not really

Answer 11

Ok.
http://www.mathsisfun.com/sets/function.html
I think this would help you.

Answer 12

Each oval on the left represents the INPUTS; each oval on the right represents the OUTPUTS.

How do you determine whether or not you have a function in each case? Look at all of the members of the DOMAIN. If ONLY ONE member of the OUTPUT set connects with each member of the DOMAIN, you have a function. If, on the other hand one member of the input set connects with TWO or more members of the output set, you do NOT have a function.

Answer 13

Time for pray - 15 min - and I will be back In Sha' Allah!
Salam!

Answer 14

Think: "One to one." Not one to two, not one to three, and so on.

Answer 15

Look at situation #1. The four members of this set of INPUTS are 4, 5, 6 and 7.
Check: That 4 "maps" onto how many members of the OUTPUT set?

Answer 16

okay so it should simply be one to one, thats where I was getting confused

Answer 17

@mathmale

Answer 18

that would mean 2 and 4 are the answers?

Answer 19

and 3 too

Answer 20

Yes. One to one => you have a function.
Two input values have the same output value => you have a function

Answer 21

One input value has 2 or more output values associated with it => you do NOT have a function

Answer 22

so just 2 and 4

Answer 23

So, which of the four cases is NOT a function? Explain.

Answer 24

number 1 because for one input there is more than 1 output

Answer 25

In #1 I see that input values 4, 5 and 6 map to 2 in the set of output functions. Anything wrong with that?

Answer 26

yes well that wouldn't be a function

Answer 27

For #1 I see that all four members of the input set map on to ONLY ONE member of the output set; that means "one to one."

But you're saying this is not a function. Why?

Answer 28

What about "7" in the input set? is this one to one or not one to one?

Answer 29

oh i got confused,, i thought that if there is more than one output on an input value it is not a function

Answer 30

That's absolutely right.
So, #1 does not represent a function.

Answer 31

like ofr example 4,5,6 are a;; on 2 so thats why I thought it is not a function

Answer 32

oh so I'm right

Answer 33

yes, you are: #1 is not a function because 2 different output values are associated with input value 7.

Answer 34

2 is a function because there is a put put value for every input?

Answer 35

put put? please explain

Answer 36

input****

Answer 37

better. Actually, you look at each member of the INPUT set and ask yourself how many members of the OUTPUT set are connected to each.

Answer 38

Only 2, 4, 6 and 10 are connected to some member of the OUTPUT set. Does 2 have connections to more than one value in the output set?

Answer 39

No

Answer 40

it is a function

Answer 41

Right. If you ask yourself the same question in regard to inputs 4, 6 and 10, your answers would be the same. Thus, this relationship is one to one and is a function.

Answer 42

so knowing this I know that #4 is not a function because there is an input that has more than one output

Answer 43

Exactly right. Very good!

Answer 44

and 3 is because there is one output for each input

Answer 45

Exactly right.

Answer 46

Say "ONLY one output for each input."

Answer 47

Happy to work with you. See you again, soon.
Over and out.