Question

Mechanics

Answer 1

Solve >>

Answer 2

Side note : It's a general motion (rotation + translation)

Answer 3

Hints:
Step 1:
Find the instantaneous centre of rotation (ICR) which you would have worked on before.
Step 2:
The angular velocity would be in the ratio
\(r_1\omega 1=r_2\omega_2 \)
by equating the displacements at the junction point B.

Answer 4

The instantaneous center of rotation, can't find it here.

Answer 5

I found the speed of b

Vb = 12 * 0.6 = 7.2 m/s

Answer 6

Excellent, that means you know your ICR.
Yes, so the ICR can be considered stationary at C.

Answer 7

so Vc = 0 ?

Answer 8

VB = W(BC) * CB

W(BC) = 7.2/ 1.2 = 6 rad /s ?

Answer 9

Yes, the instantaneous velocity Vc=0 because the motion of point B is perpendicular to both A and C.

Answer 10

so when two velocities are perpendicular and the perpendicular in the velocity vector intersect one of them , it's the ICR

Answer 11

yes, and \(\omega_{BC}=0.6*12/1.2=6 \) rad/s.

Answer 12

Thanks, I will continue solving the problems.

Answer 13

Very good!
Please post in the engineering section (I suppose you're doing engineering mechanics) and post a link here if you want the crowd to see your problem.
I will be out most of the day. If you have other questions, try tagging @rvc if you need help from someone who knows this stuff!