Question

Please help, its urgent :(((
The sum of the roots of
x^2 +px+2=0
is equal to twice the product of the roots of
3x^2 +4x-2(p+1) =0. Find the values of P

Answer 1

Sum of roots = -b/a
Product = c/a

Where a b and c are the coefficients in standard quadratic equation

Answer 2

so would it be
-p/1 = 2(-2/3) ?

Answer 3

The -p/1 is correct

But c = -2(p+1)

Answer 4

And the a in second equation is 3

Answer 5

how would i solve this though- can i do it straight as -p = 2(p+1) ?

Answer 6

\[Product~of~roots=\frac{ c }{ a }\]\[Given~eq.~is~3x^2+4x-2(p+1)=0\]
\[Product ~of~roots=\frac{ -2(p+1) }{ 3 }\]
\[\frac{ p }{ 1 }=2*\frac{ -2(p+1) }{ 3 }\]
3p=-4p-4
find p