Pre-Calculus Help? I've been stuck on this problem for a while, so I was wondering if anyone could help walk me through solving it? Find the point on the terminal side of θ = -3pi/4 that has an x-coordinate of -1
This point in the third quadrant.
Think about isosceles triangle
Let O be the origin Let M=(-1,0) and the N=(1,y) our point The triangle OMN is a right isosceles triangle. ON=y=?
Are you with me?
Yeah, I think so, but I'm still not understanding how exactly to find the y coordinate
draw a picture and you can find out how much is y
I did, but I still don't get it. I think it's supposed to be solved with the unit circle somehow
My textbook really sucks at explaining things. This problem is from a lesson based off of trig functions though
I see what you mean, but how do you know for sure that it goes down that far? Is there a way to algebraically explain it?
Wait a second
Ok
You see the arc is the angle - 3pi/4
Yeah I see that
So is the only way to explain it through graphing like that? There's no algebraic way to solve it?
intersect the line coming from the origin to the tip of the arc and the line x=-1, you get your terminal point
This is the easiest way to do it
That is a proof and you can take it to the bank
Trigonometry is bes understood using geometry
So there is no algebraic way to solve it? I know that geometry is easier, but I also need to know if there's an algebraic way to solve it
A picture is equal thousand of words. When you can draw a picture, use it.
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