Question

http://prntscr.com/dc9mqt

Answer 1

f(x) = a(x - h)^2 + k

Vertex: (h, k) -- Axis of symmetry, as well

Look at the end-behaviors to identify 'a'

Answer 2

so would it be negative?

Answer 3

Yes, 'a' is negative.

In f(x) = a(x - h)^2 + k, using the other point labeled, you can substitute in both the vertex and point:

-2 = a(x + 2)^2 + 1
-2 = a(6)^2 + 1
-2 = 36a + 1
-3 = 36a
a = -1/12

f(x) = -1/12(x + 2)^2 + 1

Answer 4

so would this be the final answer?

Answer 5

Yes, that would be the equation. Just, subbing f(x) for y, if you wanted