Question

Hello, could someone explain this concept of derivatives to me

Answer 1

i don't see any pie in that pic..

Answer 2

I attached the wrong photo sorry,

"Why is it that when you take the derivative of this, you don't take the derivative of pi and r^2? Pi is a constant so wouldn't it be 0 and then 2r*dr/dt?"

Answer 3

` pi and r^2`
is it pi +r^2 or `pi r^2`

Answer 4

ok

Answer 5

\[\huge\rm v= \pi r^2 \cdot h\]
we have to apply the power rule
\[\huge\rm y'= f(x)' g(x) + f(x) \cdot g'(x)\]

Answer 6

since r is constant r=8 m so only is variable and differentiate.

Answer 7

"h"

Answer 8

Oh I see, what about pi though?

Answer 9

ohh yeah its a word problem
`with radius 8 m`

Answer 10

pi is also constant.

Answer 11

Why isn't pi a "a constant" instead of a constant? Isn't it a number so the derivative of it would be 0?

Answer 12

we are only diff. variable not constant and if u wants to diff. it use product rule as above .

Answer 13

if there a variable exits.

Answer 14

Oh okay. I don't really get it yet, but as I understand a little bit so maybe as I keep doing problems it'll become clear. Thank you!

Answer 15

it's like 5x
the derivative of this would be `5` because of the variable

Answer 16

\[\huge\rm \frac{dv}{dt}= \color{Red}{ \pi r^2 }h^1\]
pi and r^2 are constant
h is a variable \[\large\rm \frac{dv}{dt}= \pi r^2 \cdot 1 \frac{dh}{dt}\]

Answer 17

if it was just pir^2 then yeah the derivative of just the `constant` would be zero.