Help with Related rates? A swimming pool is 12 meters long, 6m wide, 1m wide at the shallow end, and 3m deep at the deep end. Water is being pumped into the pool at 1/4 cubic meters per minute, and there is 1 meter of water at the deep end. a. What percent of the pool is filled? b. At what rate is the water level rising?
1 meter deep* at the shallow end
Oh I see :O by shallow they just mean the left edge of the pool and it's a straight decline from there.
Yeah sorry
Lemme erase all my crap from before so we can rethink this :D
Ok, thanks so much.
the volume of the triangular prism is \[V= \frac{1}{2} b *h *w\]
you know that the height must be 1/6 of the length since the height of the triangle is 2m and the length is 12 hence we could write this as 6h=l
the rate given is 1/4 m^3/min which is volume per second aka dV/dt=.25 m^3/m
you know there is already 1 meter at the deep end or 1 meter deep hence the length of the water must be 6m from the 6h=l relation above hence you can calculate the total volume of water already existing in the pool and dub this number as the starting volume
now, a is easy, to find percentage, you need to calculate the initial volume of water and then calculate the total volume of the pool the total volume of the pool is the addition of a triangular prism along with a rectangular prism these dimensions are already given to get percentage, divide initial water volume by the total pool volume
any questions thus far?
No
Would the volume of it be 144?
volume of what? the initial volume of water or the volume of the pool?
Umm The volume of the pool
Yes, the total volume of the pool would be 144 m^3 dont forget to include units
Right.
so what is the initial volume of water?
Im not sure how to find it.
|dw:1480301848620:dw| you know the width of pool is 6 regardless of what you do, so we will ignore that for now
hence the dimensions of the triangular prism is 2x12 |dw:1480301906939:dw|
now, it states that the water is 1 meter deep|dw:1480301941181:dw| so what is the corresponding length of the triangle created by the water?
6
now, if you remember above, i stated, for the triangular portion of the pool the length will always be 6 times the height because any height you create will be a similar triangle to the big one
so yes, the length is 6m, the height is 1m what is the corresponding volume created by the water?
6*6*1=36?
triangular prism the area of the triangle times the width (1/2 *6*1)*6
Oh 18
right, you know the total volume of water and the total volume of the pool, so what percentage of the pool is filled?
18/144 Is .125 So 12.5%
yup
ok, now for part B there will actually be 2 different answers for this, depending on whether the triangular prism is being filled or is already filled up make sense?
or, let me ask, will the water level of a triangular prism rise at the same rate of the water level of a rectangular prism?
ok, anyways to do the related rates problem first identify what variables you are given and what variables you are solving for dV/dt is given- this is the rate at which water is being pumped into the pool dh/dt is the rate at which the water level is increasing
so, in order to get a equation with dV/dt, this means we would need to take the derivative of the volume equation with respect to time so, for the triangular prism, we know V= 1/2 *l *h*w
now, it is VERY importatnt to note which variables are constant in this case, only w is constant at 6m and l is dependent on h we know l=1/6 h so we substitute that in V=1/12 h*h*w
then, you take the derivative with respect to time to get an equation relating dV/dt and dh/dt
Sorry :/ Ive got to go Thank you though, very much.
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