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Mathematics 7 Online
OpenStudy (ny,ny):

Help with Related rates? A swimming pool is 12 meters long, 6m wide, 1m wide at the shallow end, and 3m deep at the deep end. Water is being pumped into the pool at 1/4 cubic meters per minute, and there is 1 meter of water at the deep end. a. What percent of the pool is filled? b. At what rate is the water level rising?

OpenStudy (ny,ny):

1 meter deep* at the shallow end

OpenStudy (ny,ny):

Wait one sec http://m.imgur.com/w40HkBW Does this help

zepdrix (zepdrix):

Oh I see :O by shallow they just mean the left edge of the pool and it's a straight decline from there.

OpenStudy (ny,ny):

Yeah sorry

zepdrix (zepdrix):

Lemme erase all my crap from before so we can rethink this :D

OpenStudy (ny,ny):

Ok, thanks so much.

OpenStudy (sooobored):

the volume of the triangular prism is \[V= \frac{1}{2} b *h *w\]

OpenStudy (sooobored):

you know that the height must be 1/6 of the length since the height of the triangle is 2m and the length is 12 hence we could write this as 6h=l

OpenStudy (sooobored):

the rate given is 1/4 m^3/min which is volume per second aka dV/dt=.25 m^3/m

OpenStudy (sooobored):

you know there is already 1 meter at the deep end or 1 meter deep hence the length of the water must be 6m from the 6h=l relation above hence you can calculate the total volume of water already existing in the pool and dub this number as the starting volume

OpenStudy (sooobored):

now, a is easy, to find percentage, you need to calculate the initial volume of water and then calculate the total volume of the pool the total volume of the pool is the addition of a triangular prism along with a rectangular prism these dimensions are already given to get percentage, divide initial water volume by the total pool volume

OpenStudy (sooobored):

any questions thus far?

OpenStudy (ny,ny):

No

OpenStudy (ny,ny):

Would the volume of it be 144?

OpenStudy (sooobored):

volume of what? the initial volume of water or the volume of the pool?

OpenStudy (ny,ny):

Umm The volume of the pool

OpenStudy (sooobored):

Yes, the total volume of the pool would be 144 m^3 dont forget to include units

OpenStudy (ny,ny):

Right.

OpenStudy (sooobored):

so what is the initial volume of water?

OpenStudy (ny,ny):

Im not sure how to find it.

OpenStudy (sooobored):

|dw:1480301848620:dw| you know the width of pool is 6 regardless of what you do, so we will ignore that for now

OpenStudy (sooobored):

hence the dimensions of the triangular prism is 2x12 |dw:1480301906939:dw|

OpenStudy (sooobored):

now, it states that the water is 1 meter deep|dw:1480301941181:dw| so what is the corresponding length of the triangle created by the water?

OpenStudy (ny,ny):

6

OpenStudy (sooobored):

now, if you remember above, i stated, for the triangular portion of the pool the length will always be 6 times the height because any height you create will be a similar triangle to the big one

OpenStudy (sooobored):

so yes, the length is 6m, the height is 1m what is the corresponding volume created by the water?

OpenStudy (ny,ny):

6*6*1=36?

OpenStudy (sooobored):

triangular prism the area of the triangle times the width (1/2 *6*1)*6

OpenStudy (ny,ny):

Oh 18

OpenStudy (sooobored):

right, you know the total volume of water and the total volume of the pool, so what percentage of the pool is filled?

OpenStudy (ny,ny):

18/144 Is .125 So 12.5%

OpenStudy (sooobored):

yup

OpenStudy (sooobored):

ok, now for part B there will actually be 2 different answers for this, depending on whether the triangular prism is being filled or is already filled up make sense?

OpenStudy (sooobored):

or, let me ask, will the water level of a triangular prism rise at the same rate of the water level of a rectangular prism?

OpenStudy (sooobored):

ok, anyways to do the related rates problem first identify what variables you are given and what variables you are solving for dV/dt is given- this is the rate at which water is being pumped into the pool dh/dt is the rate at which the water level is increasing

OpenStudy (sooobored):

so, in order to get a equation with dV/dt, this means we would need to take the derivative of the volume equation with respect to time so, for the triangular prism, we know V= 1/2 *l *h*w

OpenStudy (sooobored):

now, it is VERY importatnt to note which variables are constant in this case, only w is constant at 6m and l is dependent on h we know l=1/6 h so we substitute that in V=1/12 h*h*w

OpenStudy (sooobored):

then, you take the derivative with respect to time to get an equation relating dV/dt and dh/dt

OpenStudy (ny,ny):

Sorry :/ Ive got to go Thank you though, very much.

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