PLEASE HELP The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is at negative 5, 5. Point B is at negative 4, negative 2. Point C is at 2, 1. Point D is at negative 2, 4. Point E is at 2, 4. Point F is at 3, negative 4. Part A: Using the graph above, create a system of inequalities that only contain points D and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points)
Part B: Explain how to verify that the points D and E are solutions to the system of inequalities created in Part A. Part C: Timothy can only attend a school in his designated zone. Timothy's zone is defined by y < 3x − 3. Explain how you can identify the schools that Timothy is allowed to attend. (2 points)
@misty1212
please help me
I could but I'm not good at it unless I can see the graph sorry
i can send a piture of it if needed
please help
The concept is easy. The math is a little tough. The inequalities you want to write are in the form of lines The points D and E can both be shown to be above two lines. Can you name them? use the points to name the lines for example greater than AB would be a shaded area from a line between points A and B that includes points C, D, E and F It is very confusing but try to answer my question.
ok
y>3 and x>-3. Shade above y=3 and to the right of x-3
is that right?
Yes that does work. I just thought they wanted us to somehow incorporate the lines between the schools. I was thinking one line would be greater than AC and the other line would be greater than BC. The shaded area of those two lines would include D and E. But your answer also seems to work and I don't see anything in the instructions that I have to use the school points in my description of the lines.
so what's the answer?
What is part A, B, and C
@AloneS @Elsa213
@GIitter
Please help me I really need help I have been working on this for 9 hours
@22chocolate22
ok, we want to draw 2 lines such that when we shade the area between those 2 lines, that area will only cover points D and E do you understand?
a little
so the 2 lines could be |dw:1480473446999:dw|
ok
or |dw:1480473479415:dw|
ok so what do I put for Part A?
or |dw:1480473506112:dw| as long as whatever region you shade contains D and E
well, you would first need to determine what lines you want to draw and the equations of those lines
y>3 and x>-3. Shade above y=3 and to the right of x-3
is that one or no
one sec, let me draw it out
yea, those inequalities and instructions are perfect
ok
yaya
A and C are not included in the region so you;re golden
so I can put those down for Part A?
of course... why would you not be able to? it solves what the question is asking for
ok so what is Part B?
how do you verify that point D and point E are actually within the shaded region depicted by the inequalities you wrote down
this is actually quite easy, you take the point, and you substitute it into the equations if they're true for both points in both equations, then they lie in the defined region
I don't know Im really not good at this :(
ok, so lets look at point D (-2,4)
ok
your 2 lines are y>3 x>-3
yes
is 4>3 true? is -2>-3 true?
yes
see how i substititued y=4 and x=-2 which correspond to point D
to verify you have to use both of the x,y values in the inequality?
you substitute the point into your system of inequalities, and if both statements comes out as true, then the point lies within our region
both x and y
Ok so what do I put down specifically for Part B:
Are you still there?
you substituted the points into your inequalities and all statements were true something along those lines
ok thankyou can you help me with Part C:?
ok, look at the graph they gave you, draw the line y = 3x − 3 then determine which region of the line satisfies y < 3x − 3 lastly, determine which points are in that region
one note, any points that happen to lie on the line of y = 3x − 3 do not count since the actual inequalities if less than and not less than or equal to.
Im not good at graphing
ok so is it c or F
yup
|dw:1480474536545:dw|y-intercept is -3
ok So he can go to either the C or the F school for Part C?
slope is 3 |dw:1480474566848:dw|
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