Given: ΔABC is a right triangle. Prove: a2 + b2 = c2
The following two-column proof with missing justifications proves the Pythagorean Theorem using similar triangles: Statement Justification Draw an altitude from point C to Line segment AB Let segment BC = a segment CA = b segment AB = c segment CD = h segment DB = y segment AD = x y + x = c c over a equals a over y and c over b equals b over x a2 = cy; b2 = cx a2 + b2 = cy + b2 a2 + b2 = cy + cx a2 + b2 = c(y + x) a2 + b2 = c(c) a2 + b2 = c2
Which is not a justification for the proof? Pieces of Right Triangles Similarity Theorem Side-Side-Side Similarity Theorem Substitution Addition Property of Equality
I'm thinking the answer is B, but i am not 100% sure. Please someone help me. Thank you!
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http://jwilson.coe.uga.edu/emt668/emt668.student.folders/headangela/essay1/Pythagorean.html
Read the following Bhaskara's Second Proof of the Pythagorean Theorem in the above link
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