Describe the behavior of the graph at the x-intercept for the function f(x)=(2x-7)^7(x+3)^4 I know what to do I just need a little guidance and have a couple of questions. Please help I will fan and medal!!!
Im not sure if this is a question where you will list the doman, range, x intercept and all of that other stuff
or if you are just listing the x intercepts
I think they want to know if the graph is rising, or decreasing, etc. at the x-intercepts
Oh okay, but the graph is so weird
Could you help me with finding the domain and range?
@phi ^^^^
I can do everything else
f(x)=(2x-7)^7(x+3)^4 domain: you start by assuming the domain is all x then remove any "divide by zero" or "root of a negative number" we don't have any divides, and no square roots. so we can keep all x values for the domain
Okay, i get that Isn't the domain for this specific thing suppose to be something in the form of (0,infinity) (that was just a random example)
I was thinking that the domain is, (0, positive infinity)
f(x)=(2x-7)^7(x+3)^4 range: if x is "very negative" then 2x -7 will be negative. Raising it to an odd power (7 in this case), it stays negative. In other words, as we make x more negative, f(x) gets more negative. f(x) can move as far as we want toward negative infinity. on the other hand, if x is "big positive" 2x-7 is positive raising to 7th power , it's still positive ditto for x+3 and (x+3)^4 i.e. we can make f(x) move toward + infinity thus the range is \[ (-\infty , +\infty) \]
the domain is all x \[ (0, +\infty) \] leaves out negative x values, so that is not the entire domain.
Ohhhh okay this makes sense
@phi so for range would it be (-infinity, positive infinity)?
And I now understand, if it were (0, infinity) it would exclude the -3 point that it lays on and that wouldn't make sense
yes, both the domain and range are -infinity to + infinity
wolfram can graph this function http://www.wolframalpha.com/input/?i=f(x)%3D(2x-7)%5E7(x%2B3)%5E4
@phi Okay, thank you so much!!!
I was using desmos lol
@phi sorry I have two more questions For the increase would you say (0, +infinity), and for the decrease you would say (-3, 0)?
The curve f(x) rises up to the x-axis at x=-3 then turns back down. the x-axis is tangent to the curve at x= -3 at the other x-intercept, the curve rises rapidly until it is just below the x-axis at about x=2, then rises very slowly, crossing the x-axis at x= 3.5. At about x= 4.5, the curve's slope rapidly increases, and it rises rapidly
@phi okay so the increase would be (-3,0),(0,4.5)?
the curve increases from -infinity up to -3 and then from 3.5 to + infinity in between -3 and 3.5, the curve dips down and back up
@phi Oh okay, I get it now
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