Question

Will someone help me with this find the integral of (x^2+1)/square root of x

Answer 1

\[\large \int\limits_{}^{}\frac{ x^2+1 }{ \sqrt{x} }~dx=\int\limits_{}^{}\frac{ x^2 }{ x^\frac{ 1 }{ 2 } }+\frac{ 1 }{ x^\frac{ 1 }{ 2 }}~dx\]

Answer 2

Ok now, you can simplify the fractions ya?

Answer 3

ohhh right, I forgot that you can split fractions, so it would be x^3/2+1/square root of x

Answer 4

@harman.singh

Answer 5

Is that your answer for the whole integral or one fraction?

Answer 6

whole

Answer 7

@harman.singh

Answer 8

@zepdrix

Answer 9

whut :U

Answer 10

what?

Answer 11

I may just be overthinking

Answer 12

`so it would be x^3/2+1/square root of x`
\[\large\rm \int\limits x^{3/2}+x^{-1/2}~dx\]Yes, before integrating.

Answer 13

ok

Answer 14

You figure out the rest of it lady Kay? :d

Answer 15

yes 2/5x^5/2+2x^1/2

Answer 16

yay good job

Answer 17

\[2/5x^2\sqrt{x}+2\sqrt{x}+c\]

Answer 18

:)

Answer 19

I forgot you could split the fractions I was trying to do u sub lol

Answer 20

Bahhh :d

Answer 21

lol what?