Question

Pre-Cal Help!
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Answer 1

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Answer 2

Encode the year.

For 1991, 1991 - 1991 = 0, so use t = 0 for 1991
For 1995, 1995 - 1991 = 4, so use t = 4 for 1995
For 2011, 2011 - 1991 = 20, so use t = 20 for 2011

Your task is to find C(t) = 0.60 and then UNencode the result to a year.

If you get C(q) = 0.60, then the proper year is q + 1991.

It's all about the encoding.

Answer 3

Yeah this is all gibberish to me. XD sorri ;-; Hold on. I read the question and what does t mean?

Answer 4

Wait so I would plug in .60 for t and solve?

Answer 5

What to do is already there. Read very carefully.

If you get C(q) = 0.60, then the proper year is q + 1991.

Does that look like t = 0.60, like you asked, or something else?

You need C = 0.60.

Answer 6

2007?

Answer 7

C(q) = 0.29(1.046)^{q} = 0.60

1.049^{q} = 0.60 / 0.29 = 2.069

q*log(1.049) = log(2.069)

q = log(2.069) / log(1.049) = 0.31576 / 0.02078 = 15.195

1991 + 15.195 = 2006.2

It's possible, depending on how you are rounding, that 2007 is the correct answer.

Please look at this response as an example of how to SHOW YOUR WORK.