Question

1. A 12 kg barrel is pulled up by a rope. The barrel accelerates at 1.2 m/s2. Find the force exerted by the rope. Show all your work.
Im very confused

Answer 1

Total acceleration = (gravity + 1.2) = (9.8 + 1.2) = 11m/sec^2.
Tension force = (mass x acceleration), = 12 x 11, = 132N.

Answer 2

in order to this problem
t= tenion in the rope in +ve direaction of y axis
a = acceleration also in +ve dreaction of y axis
mg = weight of body _ve direaction of y axis
F(net)= tension + weight
\[F= T+(-mg)\]
\[T=F+mg \]
we know F= ma then tension
\[T=m(g+a)\]
put given value we get
T=12(9.8+1.2)
T=132