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Mathematics 12 Online
OpenStudy (princeevee):

help please

OpenStudy (princeevee):

OpenStudy (princeevee):

@Daniyil_the_spy

OpenStudy (steve816):

Set the two sides equal to each other. So it would be 8x - 5 = 6x + 9 Then, solve for x

OpenStudy (steve816):

And yes, opposite sides on rhombus are equal.

pooja195 (pooja195):

To add onto what @steve816 we set the two equations equal to each other because the sides of are equal to each other. We know this because the shape is a parallelogram some properties of a parallelogram include: -parallel sides <----in this case the sides are parallel :) -opposite sides are congruent - diagonals bisect each other

OpenStudy (princeevee):

i cant find whats X...

OpenStudy (steve816):

Do you know how to combine like terms? 8x - 5 = 6x + 9 Subtract 6x to both sides, you get 2x - 5 = 9 Add 5 to both sides, you get 2x = 14 Can you solve for x now?

OpenStudy (princeevee):

7

OpenStudy (steve816):

Yup! Good job :)

OpenStudy (princeevee):

okay i got a 100 on it!

OpenStudy (princeevee):

now just one more bonus question for a fan!

OpenStudy (princeevee):

OpenStudy (princeevee):

@563blackghost

OpenStudy (princeevee):

hi

OpenStudy (princeevee):

@Daniyil_the_spy

OpenStudy (daniyil_the_spy):

hi

563blackghost (563blackghost):

This should help... According to the chart `DG` is `1/3 of AD` and `AG is 2/3 of AD`

OpenStudy (daniyil_the_spy):

I agree

OpenStudy (princeevee):

not that well with fractions......

563blackghost (563blackghost):

`AD` equals `45cm`. \(\huge\bf{AG=\frac{45 \times 2}{3}}\) \(\huge\bf{DG=\frac{45}{3}}\)

OpenStudy (princeevee):

bonus bonus question!!!!

OpenStudy (princeevee):

OpenStudy (princeevee):

@563blackghost @Daniyil_the_spy

563blackghost (563blackghost):

OpenStudy (princeevee):

im right.

563blackghost (563blackghost):

Parallelograms have two parallel pairs that are opposite from each other. So we would have to find the slope of each. Let's do Sarah's first. Sarah's guesswork: \(\huge\bf{AB=\frac{6-1}{1-4}}\) \(\huge\bf{BC=\frac{4-6}{-4-1}}\) \(\huge\bf{CD=\frac{-1-4}{-1+4}}\) \(\huge\bf{DA=\frac{-1-1}{-1-4}}\) Justin's guess work: \(\huge\bf{AC=\frac{4-1}{-4-4}}\) \(\huge\bf{BD=\frac{3-6}{9-1}}\) \(\huge\bf{BC=\frac{4-6}{-4-1}}\) \(\huge\bf{DA=\frac{3-1}{9-4}}\)

563blackghost (563blackghost):

Sorry it's quite long. I took a while cause I was making sure the equation were correct.

OpenStudy (princeevee):

is it okay if i have the complete versions of the division problems/fractions? like i said, im not good at them...

OpenStudy (princeevee):

@563blackghost

563blackghost (563blackghost):

Sorry I can not do that :( I can check if you do them correctly, just post up the solutions you got ;)

OpenStudy (princeevee):

can you at least help me along with every one of them?

563blackghost (563blackghost):

Sarah's guesswork: \(\huge\bf{AB=\frac{6-1}{1-4}}\) Let's first subtract. \(\huge\bf{AB=-\frac{5}{3}}\) That's the slope of `AB`.

OpenStudy (princeevee):

ok

563blackghost (563blackghost):

\(\huge\bf{BC=\frac{4-6}{-4-1}}\) We subtract to... \(\huge\bf{BC=\frac{-2}{-5} \rightarrow \frac{2}{5}}\)

563blackghost (563blackghost):

\(\huge\bf{CD=\frac{-1-4}{-1+4}}\) Subtract. \(\huge\bf{CD=-\frac{5}{3}}\)

563blackghost (563blackghost):

\(\huge\bf{DA=\frac{-1-1}{-1-4}}\) Subtract. \(\huge\bf{DA=\frac{-2}{-5} \rightarrow \frac{2}{5}}\)

OpenStudy (princeevee):

okay

OpenStudy (princeevee):

do i put it in the calculator?

563blackghost (563blackghost):

Yea that works to solve for the slope. Just place it right. EX. `(-1-1)/(-1-4)`

OpenStudy (princeevee):

so the answer to the ex is 2/5 right?

563blackghost (563blackghost):

Correct :) Due to the fact `DA = BC` and `AB = CD` her point does make it in a parallelogram. Now we check Justin's. Can you possibly do this?

OpenStudy (princeevee):

can we work on the others then?

563blackghost (563blackghost):

\(\huge\bf{AC=\frac{4-1}{-4-4}}\) Subtract. \(\huge\bf{AC=-\frac{3}{8}}\)

563blackghost (563blackghost):

\(\huge\bf{BD=\frac{3-6}{9-1}}\) \(\huge\bf{BD=-\frac{3}{8}}\)

563blackghost (563blackghost):

\(\huge\bf{BC=\frac{4-6}{-4-1}}\) Subtract. \(\huge\bf{BC=\frac{-2}{-5} \rightarrow \frac{2}{5}}\)

563blackghost (563blackghost):

\(\huge\bf{DA=\frac{3-1}{9-4}}\) \(\huge\bf{DA=\frac{-2}{-5} \rightarrow \frac{2}{5}}\)

563blackghost (563blackghost):

Due to the fact `AC = BD` and `BC = DA` then Justin's point does make it into a parallelogram. So what is your conclusion?

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