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Mathematics 17 Online
OpenStudy (jabez1777):

http://prntscr.com/ddf59u

OpenStudy (jabez1777):

@harman.singh

OpenStudy (harman.singh):

Notice that \[\sqrt{20}=\sqrt{5} \times \sqrt{4}\]

OpenStudy (jabez1777):

Haan :)

OpenStudy (harman.singh):

\[\sqrt{5} \times \sqrt{4} = \sqrt{5} \times 2\]

OpenStudy (hocuspucus292333393):

I was gonna help too ):

OpenStudy (harman.singh):

So the first equation 4 sqroot of 20 can be written as \[4 \times 2 \times \sqrt{5}\]

OpenStudy (hocuspucus292333393):

its equals - /5

OpenStudy (jabez1777):

Acha (y)

OpenStudy (harman.singh):

Do you know how to do the rest now?

OpenStudy (jabez1777):

Um not really... :/

OpenStudy (will.h):

alright so i can help you but what if pooja came in and remove my answers again LMAO

OpenStudy (jabez1777):

She's nice. :p

OpenStudy (will.h):

convert that expression into rational expression to get \[20^(1/4) - 45^(1/3) = 1.44\] which is equivalent to D

OpenStudy (will.h):

and yeah sure she is lol

OpenStudy (harman.singh):

So this is how you would simplify 4/20 \[4\sqrt{20}\] - write the squareroot value as multiplication of two different squareroots \[=4 \times \sqrt{5} \times \sqrt{4}\] - We know that sqroot of 4 is simply 2. So we can simplify it further in the next step \[4 \times \sqrt{5} \times 2\] - We now multiply the two like terms together.. \[8\sqrt{5}\]

OpenStudy (jabez1777):

OKay, I got that

OpenStudy (harman.singh):

Badia. Now its the same procedure for the other term in the question. \[4\sqrt{20}-3\sqrt{45}\] \[8\sqrt{5}- ???\] Can you try and simpify 3/45? I will help you if you get stuck anywhere

OpenStudy (jabez1777):

Okay but 45 doesn't have a perfect square... :/ How will you do that?

OpenStudy (harman.singh):

Think about the numbers that multiply together to give you 45. Can you list them for me please?

OpenStudy (jabez1777):

9 x 5

OpenStudy (jabez1777):

9 has a perfect square of 3

OpenStudy (harman.singh):

Haan sahi :) So we can write /45 as: \[\sqrt{5} \times \sqrt{9}\]

OpenStudy (jabez1777):

So -/5 x -/9 x 3?

OpenStudy (harman.singh):

Is that a negative sign in front of /5 & /9? Not sure what that really means

OpenStudy (jabez1777):

no lol sqroot

OpenStudy (harman.singh):

Oh achla lol. But its correct so far :)

OpenStudy (jabez1777):

-/105

OpenStudy (harman.singh):

Umm...I am not sure where you are getting 105 from. So we had.. \[\sqrt{5} \times \sqrt{9} \times 3\] As you said above, 9 is a perfect square of 3. So we can write -/9 as 3. \[\sqrt{5} \times 3 \times 3\]

OpenStudy (jabez1777):

okay so then the answer is either 45 or 135 :/

OpenStudy (harman.singh):

I am not sure how you are getting 135? Can you refer to my working out for the previous expression and see what I did there at the same step for this expression?

OpenStudy (jabez1777):

yeah i did 5 x 3 x 3 and got 45

OpenStudy (harman.singh):

Dont forget that its -/5 , not just 5

OpenStudy (jabez1777):

So how would you do that then? :/

OpenStudy (harman.singh):

You should leave the sqroot of 5 written as it is in the answer. \[\sqrt{5} \times 3 \times 3\] \[=9\sqrt{5}\]

OpenStudy (harman.singh):

and thats the simplified version of 3-/45 The original question was.. \[4\sqrt{20}- 3\sqrt{45}\] and we found simplified versions of both the equations above. Now, can you write those simplified answers togeher so that we can substract them from each other?

OpenStudy (jabez1777):

So we just subtract 3 from 4 and 45 from 20

OpenStudy (harman.singh):

No, thats the question. We have to write it in simplified form before subtracting. We found that .. 4-/20 = 8-/5 & 3-/45 = 9-/5 So, \[4\sqrt{20}-3\sqrt{45}\] = \[8\sqrt{5}-9\sqrt{5}\]

OpenStudy (harman.singh):

Now, we can subtract the two terms from each other to simplify our answer further

OpenStudy (jabez1777):

-7?

OpenStudy (harman.singh):

When subtracting, leave the sqroot of 5 as it is. You can think of sq5 as 'x' So.. 8x - 9x = ?

OpenStudy (jabez1777):

-1

OpenStudy (harman.singh):

haan. -1x to be more precise.

OpenStudy (harman.singh):

Now replace sq5 with 'x' in your final answer.

OpenStudy (jabez1777):

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