Question

Help please

Answer 1

What's up? Whatcha need help with?

Answer 2

Okay give me just a moment to solve it out :)

Answer 3

Of course =)

Answer 4

g(16)= sqrt(16)=4
f(g(16))= 4+2 = 6
That is part one. ^^

f(g(x))= g(x) + 2 = sqrt(x) +2
That is part two. ^^

Domain of g(x) is all real numbers and the range is g(x)>_0. f(x) is defined for all real numbers in the range of g(x). Thus is the domain of f(g(x))) is all real number.

Answer 5

\[f( \sqrt 16) = (\sqrt 16) +2\] The setup for part one ;p where \[\sqrt 16 = g(16)\]

Answer 6

Sorry not the *))) on the last X only two :)

Answer 7

I think Shadow has the same idea, though he's putting it in the equation so it reads better! :)

Answer 8

Okay so is that part 1?

Answer 9

I gave the whole thing. Shadows is part one.

Answer 10

Okay @Angel.Candy thank you so much ! =)

Answer 11

Wait for part 1 there are 2 parts

Answer 12

@angel.candy

Answer 13

For part one there are two steps

Step one is asking you for the value of sqrt of 16, which is 4.

Step two is essentially asking you for sqrt of 16 plus two

Answer 14

All that is the whole entire questions i did.

Answer 15

"
g(16)= sqrt(16)=4
f(g(16))= 4+2 = 6
That is part one. ^^
"

From @Angel.Candy 's post. That is both steps.

Answer 16

Yeah, Z I did the whole thing. I didn't leave anything out. I promise.

Answer 17

Thanks beautiful and thank you sir @ShadowLegendX

Answer 18

mhm

Answer 19

Of course!