Question

Help please xx

Answer 1

g(f(x)) = g(-4x+3)
=> g(f(x)) = 1/[(-4x+3) + 2]
=> g(f(x)) = 1/(5 − 4x)

the domain of g(f(x)) is {x ∈ ℝ : x ≠ 5/4} as x = 5/4 would result in division by zero.

Answer 2

Okay so you have all the parts in order right, I just write as is?

Answer 3

Yep :)

Answer 4

and the domain ? Its not quite clear :/ how would I write that on paper

Answer 5

The domain would result in zero. g(f(x)) is not defined for 1/0, no number is defined when divided by zero, therefore it is a restriction upon the function as it cannot give an image where the denominator is zero.
Therefore (5 - 4x) = 0
5 = 4x
1.25 = x
Hence g(f(x)) has the restriction x =/= 1.25

Answer 6

So if I'm understanding you correctly the domain is 0? and that is how I would write it on paper

Answer 7

No, no. A restricted domain results when the denominator is zero, sorry I didn't explain well. Your restriction would be 1.25 because of

herefore (5 - 4x) = 0
5 = 4x
1.25 = x
Hence g(f(x)) has the restriction x =/= 1.25

Answer 8

So the domain is ?

Answer 9

x=/=1.25

Answer 10

Yes that is the restricted domain

Answer 11

:)

Answer 12

and that is the only answer right for step 3?

Answer 13

yes. :)

Answer 14

Thanks babe <3

Answer 15

<3