How is a projectile’s initial speed related to its height and horizontal displacement?

Question

billyjean · Answer

@paki

parthkohli · Answer

Well, what do you know about projectiles to begin with?

billyjean · Answer

I only know that a projectile is a missile designed to be fired from a rocket or gun.

parthkohli · Answer

So the math part of it?

billyjean · Answer

i dont know im confused

parthkohli · Answer

Well, alright. So do you know equations of motion?

billyjean · Answer

no

parthkohli · Answer

Aw man, I can't help you out then

billyjean · Answer

why

parthkohli · Answer

you need to be familiar with the basics to figure this out

billyjean · Answer

v = u + at	From acceleration definition
s = ½ (v+u) × t	Average velocity is ½ (v+u) 
s = ut + ½ at²	No 'v' needed
v² = u² + 2as	No 't' needed

billyjean · Answer

is that it

billyjean · Answer

@3mar

3mar · Answer

Oh 
I was checking that question before and have prepared something for it, but it was closed!

bugman954 · Answer

Simple the greater the speed the greater the height and horizontal displacement

vipulrakta · Answer

|dw:1480567921789:dw| and the relation between u; h , r is$$H = (u ^{2}\sin ^{2} \theta) / 2g ,  R=(u^{2} \sin 2\theta )/g$$ grater the initial speed more is horizantal distance and hight is more ance vice versa  .  R is maximum when angle = 45