Question

I need help with this.

Answer 1

At what value of x will this determinant be equal to 0 in mod 11?
\[\large \left[\begin{matrix}4 & 4 \\ x & 8\end{matrix}\right]\]

Answer 2

So I know that 32 - 4x = 0 (mod 11) but I don't know how to calculate this with the modulus.

Answer 3

Here mod doesn't mean modulus. It mean remainder when divided by 11

Answer 4

Correct me if I am wrong...

Answer 5

Sorry, I just meant modular arithmetic

Answer 6

work out x

Answer 7

Amod(n)=r
where r is the remainder of A divided by n

Answer 8

14 mod 11 =r
14/11=1 remainder 3

r=3

Answer 9

where r is the remainder

Answer 10

Yeah that's what I meant

Answer 11

Wait, I don't understand what you did :( Where did you get 14 from??

Answer 12

I was using this as an example

Answer 13

work out x first, then in
Amod(n)=r

let A be the answer of x
n=11

Answer 14

do x/11
then get the remainder

(this should be a triple equal sign)

Answer 15

8/11 (mod 11) = 8 right?

Answer 16

yes because 11 goes into 8, zero times, with a remainder of 8

Answer 17

ok ty, I need help with one more problem like this that is similar.