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Mathematics 8 Online
OpenStudy (daniyil_the_spy):

plz help ary man or anybodt rely

OpenStudy (daniyil_the_spy):

Simplify the rational expression.

OpenStudy (daniyil_the_spy):

OpenStudy (daniyil_the_spy):

@damir

OpenStudy (daniyil_the_spy):

@satellite73

OpenStudy (daniyil_the_spy):

@Directrix

OpenStudy (daniyil_the_spy):

oh thx 4 comen

satellite73 (satellite73):

i suck at factoring , but that is what you have to do, factor and cancel

OpenStudy (damir):

i am here no worries

satellite73 (satellite73):

\[x^2+4x-21=(x+7)(x-3)\] pretty sure now factor the bottom

OpenStudy (damir):

that is it

satellite73 (satellite73):

all though you have narrowed it down to B or C because the numerator will be \(x-3\)

OpenStudy (daniyil_the_spy):

thx

OpenStudy (daniyil_the_spy):

I have another Q

satellite73 (satellite73):

you still have to factor the denominator though

OpenStudy (unklerhaukus):

what two integers multiply to give 42, and add to give 13?

OpenStudy (daniyil_the_spy):

Its C guys

OpenStudy (daniyil_the_spy):

OpenStudy (daniyil_the_spy):

@satellite73 @damir

OpenStudy (daniyil_the_spy):

@mathmale

OpenStudy (daniyil_the_spy):

@mathmate

OpenStudy (daniyil_the_spy):

@mathmale

OpenStudy (mathmate):

Put the numbers in and use your calculator to find the rate of discount: P=regular Price=$28 D=discount=regular price - sale price = $28-$20 R=Rate of discount = \(\Large R-\frac{P-D}{P}\) Use your calculator to find R. You can also use common sense to find the answer: 1. rate of discount can never be greater than 1, otherwise the seller would be paying you to give you the sweater. 2. In this case, the sweater was sold at 20 out of 28, so the discount did not exceed half of the original price. Based on the above, you can find the answer (out of the four choices) Finally, the given formula is overly complicated, no wonder students (sometimes) find math difficult. The same answer could be simply \(\Large R=\frac{D}{P}\), or \(\Large R=1-\frac{S}{P}\), where S=sale price

OpenStudy (daniyil_the_spy):

thx @mathmate

OpenStudy (mathmate):

You're welcome! :)

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