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Mathematics 11 Online
OpenStudy (sabasattar):

A statistics instructor randomly selected four bags of​ oranges, each bag labeled 10​ pounds, and weighed the bags. They weighed 10.4, 10.7, 10.3​, and 10.8 pounds. Assume that the distribution of weights is Normal. Find a​ 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. What are the lower and upper bounds of this confidence interval?

OpenStudy (lgnd_88):

The CI is calculated using the formula x-bar +/- t-alpha/2 * sigma / sqrt(n) x-bar is the average of the numbers = 9.525 sigma is the standard deviation of the numbers = 0.15 Since there are a small number of samples you have to use the student t distribution to calculate t-alpha /2. The number of samples is 4, so the degrees of freedom is 3. You want a 95% CI. Using the table at the web site http://www.sjsu.edu/faculty/gerstman/Sta... t-alpha/2 is 3.182 So the CI is 9.525 +/- 3.182 * 0.15 / sqrt(4) = (9.29, 9.76)

OpenStudy (lgnd_88):

Hope that helps^^

OpenStudy (sabasattar):

Thank you so much!

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