Find the value of x and y. medal and fan https://static.k12.com/eli/bb/343/5_23951/2_15047_5_23956/5709fbfaa75088042bab65545a4ec16587cd7dfc/media/e15e4eef5730aae321a30bdcb992736ba71a4d72/mediaasset_649626_1.gif
help?
The 2 short sides of this trapezoid are of equal length, and at first glance that length appears to be 12. Have you considered setting 2x+3y equal to 30x+11y? Alternatively, you could set 2x+3y=12 and 30x+11y=12. Experiment. Can you solve for x and y?
@mathmale I'm cluless
I think maybe the 30x+11y is the size of the angle, and you would get simultaneous equations?
tell me thats not true @m
I'd suggest you follow amorfide's suggestion. Assume that 30x+11y is the measure of an angle. Equate 30x+11y to 112 (which is the measure of the other obtuse angle). Set 2x+3y=12. This gives you a system of equations. Try solving it for x and y. Note that both x and y must be positive for this solution to make sense.
How have you solved systems of linear equations in the past? Among other possible approaches, you could try substitution, elimination by addition/subtraction, graphing, matrices, determinants.
ok well that one cant be anwserd could we try another one
Let's see your actual work before you tell me that this particular problem can't be solved.
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