Calculus question! "5.1: Areas and Distances"
"Estimate the area under the graph of \(g(x)=\frac{5}{1+x^2}\) from \(x=-2\) to \(x=2\) using 4 rectangles at right endpoints."
Riemann sums? I haven't done these sorts of problems in a long while - but I can try to help ^_^ @kittybasil
Sure, go ahead :)
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ehhh so the idea of riemann sums is to add up rectangles in order to estimate the area under a curve
Yup, got that :)
what they mean by "right endpoints" means that the right corner of these rectangles should be the points touching the given function
|dw:1480794062035:dw|
Ahh, I see. :O
they want the range of -2 to 2 and they want to estimate using 4 points thankfully, the way they ask this means that the points end up on whole number values x = -1, 0, 1, and 2
this means that the base of every rectangle here is = 1
Got it :)
Then to find the area of each of these rectangles - we need the height, right? how do you think you can get the height of each rectangle? :3
f(x)?
The y-coordinate/output function, I mean.
yup! you can plug in the x values I listed before to get the respective heights ^_^ that's right :)
and then you just add up all the areas of the rectangles to get the answer ;P
Okay, I think I've got that too. My main issue is how to put that in Riemann sum form e_e
there's a form? ehhhh maybe it's like answer = (base)*(sum of heights) = (1) * ( f(-1) + f(0) + f(1) + f(2) )
the base can be factored out because it's the same
Or whatever the \(\Sigma\) is idk
|dw:1480794686638:dw|Something like that I think?
|dw:1480794695945:dw|
is that how that works?
Ooh, okay. Thanks :D
the triangle (delta) x = base
Hmm, the medal system is wonky...
Maybe I need to refresh this page.
yeah, don't worry - I got the medal x'D it just doesn't update properly until you leave the question and come back ;)
Oh lol
the weird E symbol (sigma) the bottom number is the first number to be plugged in, incrementing at whole numbers until the top number basically, the weird equation that I drew expands to become (1) * ( f(-1) + f(0) + f(1) + f(2) ) ;P
I think it's \Sigma
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