Question

Consider the following binomial experiment: A survey shows 56% of households in Centercity own a DVD player. In a random sample of 19 households in this city, what is the probability that exactly 13 households own a DVD player?
a) 0.1052
b) 0.1051
c) 0.1053
d) 0.1049
e) 0.1050
f) None of the above.

Answer 1

can somebody help me out with this please? I did it but ended up getting a completely different number

Answer 2

I got this 0.00033481966

Answer 3

i guessed the correct answer which was d) .1049

Answer 4

I'd suggest you share your work. Seeing how you got your result helps the helper more than just seeing your proposed answer.

In this binomial probability problem, the probability that a family owns a DVD player is p=0.56. The number of samples is n=19.

You could
1) calculate the relevant probability by hand from the appropriate formula, or
2) use a calculator that has statistics capabilities built in, or
3) use a table of binomial probabilities. Which are you going to try?

Answer 5

Thank you for time anyway :)

Answer 6

*Thank you for your time anyway :)

Answer 7

Apply this formula for n=19, k=13 and p=.56

\[
\frac{n!}{k!(n-k!}p^k (1-p)^{n-k}
\]

Answer 8

If you do that, you get
\[\frac {19!}{13! 6!}0.56^{13} (1-0.56)^6 =0.104868
\]
What should be your answer