Question

How would I put in/factor 1 in y=3x^2-5x+1

Answer 1

Do you mean, how would you factor the equation?

Answer 2

yeah

Answer 3

you have to add +1 and then subtract it again

Answer 4

One of two ways to do so:
\[\LARGE \color{blue}{y=3x^2-5x+1}\]

1.factor this quadratic equation into two factors \((x+a)(x+b)\).
2.use the quadratic formula if you have found the first method is not easy!

Answer 5

y=(3x^2-5x+1+1)-1
=(3x^2-5x+2)-1
=(3x-2)(x-1)-1
that's the furthest I could factor it. However, you may also use synthetic division.

Answer 6

Or you want to complete the square of that expression?

Answer 7

@nkhanfar
Do you follow?

Answer 8

The correct awnser would be y=3x to the second power -5x+1 @nkhanfar