Construct the confidence interval for the population mean u. C equals 0.95, X equals 16.2, o= 8.0, and N equals 85. a 95% confidence interval for u is [ ], [ ]. Round to one decimal place as needed.
@IrishBoy123 If you could help here, I would be grateful! Thanks in advance.
For a big enough normal distribution, ie \(\bar x = \mu = 16.2\). The sample and population means are the same. And common sense suggests there is no point other than starting there. From z-scores, about \( 95 \%\) of the data points will lie within \(\pm 2 \sigma\)'s of the mean, ie confidence interval, ie \(x \in [ \mu - 2 \sigma , \mu + 2 \sigma]\) We adjust the variance as : \(\sigma^2 = \sigma_{normalised }^2 = \dfrac{\sigma_{sample}^2}{N} \) where \(N = 85\) so that \(\sigma \approx 0.87\) meaning that: \(x \in [ 14.46 , 17.94]\) or so I **reckon** :)
Thank you for good explanation + Thank you for your quick response!
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