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How to do 8^(-2/3)
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Hint: \[x^{-n} = \frac{ 1 }{ x^n }\]
Would that make it 1/8^2/3
Yes, now simplify it, \[\frac{ 1 }{ (8^2)^{1/3} }\]
Note \[x^{1/3} = \sqrt[3]{x}\]
4?
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Exactly!
Okay, that helped a lot. Thanks!
But wait, we're not done, it's all over 1
so we have \[\frac{ 1 }{ 4 }\]
under*
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That's what i was thinking, but in my book it has the final answer as just 4
It would be 4 if it was 8^(2/3) not 8^(-2/3)
My mistake, the question asked 2/3 not negative.
Sorry, but either way this was helpful!
Np :)
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