Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is the distance from B to B′ ?
@mathmale
@mathstudent55
It might help if you were to plot both points. Identify the horiz. distance from one point to the other, and then the vertical distance. If you draw a line from one point to the other, and then draw in the horiz. and vert. distances, you'll see you have a right triangle. How would you use the Pyth. Theorem to determine the length of the hypotenuse? That length is the distance from one of your points to the other.
Wait what
Explain in explicit detail please
I misread your quesiton. I'd suggest you follow my suggestion (above) first, since you will need to find the distance from B to B' later. Are you familiar with the Pyth. Theorem?
uh, a^2+b^2=c^2?
You need to start with polygon ABCD. Plot the 2 given points representing A and A'. Next, determine what the translation rule is, just as you did in the previous problem. Next, determine points B', C' and D'. Plot ABCD and A'B'C'D. I'd bet you'll find that the distance from B to B' is actually the same as the distance from A to A' What have you done so far?
You do need to use the Pythagorean Theorem, but that comes a bit later. Define the translation rule first.
You are not given points B, C or D. You can invest them! Just plot point A and then put B,C and D wherever you want. What is the distance from A to A'?
-3,3?
You are given points A and A' Please show me how you will calculate the distance between these two points. What does your "-3,3" represent?
Left 3, down 4* (not 3)
Subtract x1 and x2, subtract y1 and y2
right?
I*f you do that you'll ob tain the slope of the line connecting A and A'. That's not quite what you want.
You want the distance between A and A'. The horiz. change from A to A' is. .... what? The vertical change from A to A' is .... what? Square both of these results. Add the squares together. Think: Why?
shoot, I have to go rn, but I'll ask my next teacher for help since next class is math anyways. Thank you very much for the help you've given me. <3
Ok so i still can't figure it ;-;
@mathmale
You did well on this material before and can do so again. Every point on your polygon is to be translated in the same way as is Point A. So B will be translated in exactly the same way as was done with Point A. Especially if you draw this situation, you may see that the distance from A to A', the distance from B to B', and so on, is the same in each case. Find this distance, the distance from A to A'. Use the distance formula or the Pythagorean Theorem.
How do I find the distance formula, or if you could, tell me what it is?
When something like that is easy to look up, I prefer to encourage the other person (you) to look it up. Google "distance formula."
\[Distance =\sqrt{(x2−x1)^2+(y2−y1)^2}\]
that?
THAT. Perfect!!
So now I just plug in the cords for A and A'?
Yes. More accurately, plug in the coordinates (not answers) for each point, A and A'
So It'd be \[Distance =\sqrt{(-2−1)^2+(1−5)^2}\]
Yes. What is that distance? Your answer MUST be a positive quantity.
5?
Yes, very good! that, in effect, answers this whole question.
because if A to A' is , then B to B' is 5 too, right
Language. If the distance from A to A' is 5, then so is the distance from B to B'
oops xc
All set then? Satisfied?
Thank you very much, yes I'm satisfied :)
Wishing my teacher were this way ;-;
Great. Take care, great day to you. I bear you no malice. ;)
C'mere and teach my class will ya'?
Sure. There are just those small matters of housing and pay. ;)
XD Thanks anyways :P
If I come to a problem I absolutely cannot solve, i'll bug you again
con mucho gusto. de nada. bitte sehr. merci. Come bug me again, later.
yeet, bye
;)
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