Question

A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. At the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.

h=-16t^2+14+6
h=-16t^2+10+8

After 0.5 seconds, the receiver's hands and the ball will be at the same height.

The receiver's hands and the ball are at the same height at ___ ft above the ground.

Answer 1

Those equation don't make sense to me.

The 14 and the 10 should have a t variable associated with them, right?

Answer 2

h=-162^2+14+6
h=-16t^2+10+8
these?

Answer 3

yeah

Answer 4

can you help me figure it out?

Answer 5

h=-16t^2+14t+6
h=-16t^2+10t+8

I'm not sure where the -16t^t comes from, but I guess it is gravity.

Plug in for t =0.5 into either or both equations and see what you get.

Answer 6

I plugged in 0.5 and got h=24 and h=14...

Answer 7

Those are incorrect or at least not what I got using two calculators and two graphing functions.

Write down your steps one by one so I can find your mistake. I will try to figure out those values on my end.

Answer 8

I put it into wolfram alpha

Answer 9

Take a screen shot and attach it.

Answer 10

You are still using the wrong equations.

These are the correct equations. NOTE the t behind the 14 and the t behind the 10.

h=-16t^2+14t+6
h=-16t^2+10t+8

The speed of the ball 14 ft/sec is dependent on time t
The receiver jumping up at 10ft/sec is dependent on time t

Answer 11

so I plug 0.5 into those equations?

Answer 12

Do you think that would be a good way to proceed?