Write the point-slope form of the equation of a line with slope 2/5 that passes through the point (-3,-6).

Question

mathmale · Answer

You have the slope:  2/5.
You have the x-coordinate of the given point:  -3
You have the y-coordinate also:  -6

Substitute these values into the point-slope formula:$$y-y _{1}=m(x-x _{1})$$

mathmale · Answer

Note:  x_1 becomes -3.  Leave the 'y' and 'x' as they are.

jordans_openstudy · Answer

ahh im kinda confused

jordans_openstudy · Answer

-24/5 is what my calculator shows @mathmale

mathmale · Answer

Your job is to come up with the equation of a straight line, and that equation must be in point-slope form.  Your calculator won't give you this entire equation.

I gave you the general point-slope equation:$$y-y _{1}=m(x-x _{1})$$

mathmale · Answer

Here's how to get started:  Take the given slope (2/5) and use this to replace m in the given equation.  Type out your result here, please.

jordans_openstudy · Answer

y−y1=2/5 (x−x1)

I haven't done this in a while. Where exactly do the -3,-6 go?

mathmale · Answer

In my very first response to your question, I typed

You have the x-coordinate of the given point:  -3
You have the y-coordinate also:  -6

Please use this information.

Finish this:$$y-y _{1}=(2/5)(x-x _{1})$$

mathmale · Answer

Leave x and y alone.  Change only y_1 and x_1 by substituting the given values.

mathmale · Answer

Please, respond.  Do something.  Please get involved.  If you knew this material once, you could learn it again with some effort.