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Expand (3x-1)^2. Then move all of the terms to one side. Combine like terms, and you should get an answer.
Ummm
@3mar
\[(3x-1)^{2} = 9x ^{2} -6x + 1\]
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that is the answer????
No. Now we have X's on both side of the equation. We need to set the equation equal to zero remember. So lets move \[2x ^{2} + 3x\] to the other side
okay and then
Combine all of your like terms.
5x?
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\[2x ^{2} + 3x = 9x ^{2} - 6x + 1 - x ^{2}\] \[0 = (9x ^{2} - 6x + 1 -x ^{2}) - (2x ^{2} + 3x)\] Combine like terms: 0 = \[6x ^{2} - 9x +1\]
Nice presentation! @royalranger and Sorry for being late @zarkam2! Sorry, I was not here!
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