Question

im super confused on an absolute value assignment

Answer 1

i feel like i screwed my assignment up, so i need help redoing it because i'm confused

Answer 2

@Teddyiswatshecallsme

Answer 3

@sammixboo

Answer 4

@sweetburger

Answer 5

i probably need help on the 1st since i wanna see how i can do on the rest of the assignment, i do need help though

Answer 6

i can do the linear lines, i just don't know what eqauations i should put in, i know the ones i put were wrong.

Answer 7

@zepdrix

Answer 8

@mathmale

Answer 9

@satellite73 @IrishBoy123

Answer 10

yo who gave me that medal?

Answer 11

which one?? i see a bunch

Answer 12

I thought she need the help with the first one

Answer 13

i'll just put it here:
2. Another machine is used to make 10 mm long bolts. For this machine, the bolts must have an error of less than 0.1 mm to be accepted. This can be represented by |x – 10| < 0.1.

a. Write this inequality as a compound inequality without absolute value bars.

i need help making a compound inequality without absolute value bars

Answer 14

oh ok

Answer 15

Your first problem was done well, except that you haven't included units of measurement as required.

Bolt length can be anywhere between 11.8 mm and 12.2 mm.

Answer 16

\[|x-a|<p\iff -p<x-a<p\]

Answer 17

oh so i should 11.8 mm for my 1st?

Answer 18

You could write an abs. val. inequality as follows, using 12 mm as the nominal length: See the ineq. that satellite has just typed in for you.

What do you mean by "should 11.8 mm for my 1st?" Unclear.

Answer 19

i meant as if i put the measurement.]
instead of just 11.8 it should be 11.8 mm

Answer 20

i'm re looking satellite's equation, i don't know what terms and letters are which though

Answer 21

wait, i'm starting to get it now. |x−a|<p is |x – 10| < 0.1.
ima try to associate the terms with numbers and other things like that

Answer 22

There are several ways to write this inequality, which confuses matters a bit.

The expected, standard length of this bolt is 12 mm, but a length of 11.8 or one of 12.2 mm, or anywhere in between, would be acceptable.

You could write |x-12|<0.2. That takes care of all y ou were supposed to do. If this is unclear, pls ask questions.

Answer 23

i did some looking, and it looks like 0.1<x−10<0.1 is where sattelite was getting at

Answer 24

correct me if i'm wrong

Answer 25

i still want to know why i have a medal

Answer 26

almost
you are missing a minus sign

Answer 27

oh dang

Answer 28

\[\huge |x-a|<p\iff \color{red}-p<x-a<p\]

Answer 29

oh dang i actually had that, i just forgot to copy the minus sign with the equation on my word doc.

Answer 30

well it's actually 10 instead of 12 now but yeah

Answer 31

is the value x 10.99?

Answer 32

it looks like the solution is 10.99

Answer 33

I'm confused on solving the inequality @satellite73

Answer 34

which one are you doing?

Answer 35

the 2nd problem

Answer 36

\[|x – 10| < 0.1.\]
\[-0.1<x-10<0.1\] add 10 all the way across

Answer 37

oh so it's not 10.99
i'm confused because shouldn't it be between 10.99 and 9.99

Answer 38

not the way i read it, no

Answer 39

because it shoeuld have an error of less than 0.1 mm, so 10.99 is the maximum
and 9.99 is the minimum

Answer 40

i get \[9.9<x<10.1\]

Answer 41

oh, i see it now

Answer 42

so the solution is 10 then?

Answer 43

idk, i'll see how it goes.