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Trying to study for a calculus exam; How do I chain rule the second part of the equation when trying to find the derivative? y=arcsin(x)+x(sqrt(1-x^2))
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\[ y=\arcsin x+x \sqrt{1-x^2}\] Is a little bit cleaner.
\[x \sqrt{1-x^2}\] is the same as \[x(1-x^2)^{1/2}\] Then use the chain rule
Oh, duh! Thank you so much! I totally brainfarted on turning square root into \[()^{1/2}\] Thanks again!
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