Ask your own question, for FREE!
Calculus1 16 Online
OpenStudy (luckpluck):

Trying to study for a calculus exam; How do I chain rule the second part of the equation when trying to find the derivative? y=arcsin(x)+x(sqrt(1-x^2))

OpenStudy (luckpluck):

\[ y=\arcsin x+x \sqrt{1-x^2}\] Is a little bit cleaner.

OpenStudy (royalranger):

\[x \sqrt{1-x^2}\] is the same as \[x(1-x^2)^{1/2}\] Then use the chain rule

OpenStudy (luckpluck):

Oh, duh! Thank you so much! I totally brainfarted on turning square root into \[()^{1/2}\] Thanks again!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!