Question

Rewrite x^2+9 as a multiplication using complex numbers and the polynomial identity below.
u^2+v^2=(u+vi)(u-vi)

Answer 1

@ILovePuppiesLol

Answer 2

oh hi

Answer 3

@random231

Answer 4

okay so lets compare x^2+9 and u^2+v^2

Answer 5

what do you think u can be equal to?

Answer 6

@random231 x?

Answer 7

yes :) now what can be the value of v??

Answer 8

@random231 3? or 9?

Answer 9

its 3 cuz v^2 = 9

Answer 10

so put in the values in place of u and v

Answer 11

@random231 Makes sense. So I should write u^2+v^2 as x^2+3^2?

Answer 12

(u+iv)(u-iv) as (x+3i)(x-3i) thats the form you want

Answer 13

Alright. So then x^2-3i^3?

Answer 14

yes

Answer 15

Sorry typo, I meant to write x^2-3i^2 0-0 How do we get to cubed?

Answer 16

cubed?

Answer 17

"x^2-3i^3" ^2 is squared and ^3 is cubed

Answer 18

@ILovePuppiesLol ;-; random has gone missing

Answer 19

@inkyvoyd @sweetburger @ShadowLegendX

Answer 20

@ILovePuppiesLol Thx ;-; :)

Answer 21

@random231 Oh welcome back >^-^<

Answer 22

yeah ik but you dont need to find that. (x+3i)(x-3i) is your final answer.

Answer 23

@random231 Ahhh makes sense! Thank you!!

Answer 24

:) np