Question

Help please

Answer 1

@3mar

Answer 2

Well, I am here.

Answer 3

Hello =)

Answer 4

Hello!

5 min please!

Answer 5

Okay =)

Answer 6

HI!!

Answer 7

what a silly question
you want to solve \[x^2+2x-11=4\]you could add \(11\) and get \[x^2+2x=15\] then complete the square
OR
you could subtract 4 and get \[x^2+2x-15=0\] then factor or use the quadratic formula

Answer 8

my guess is that they want you to say "subtract 4" but that is just what they want, not a real answer

Answer 9

So are you sure that is what the answer may be for this question? =) @misty1212

Answer 10

@3mar are you still busy brother

Answer 11

SO sorry for that!
I can't be busy or late for you!

Answer 12

SO @misty1212
If we are going to solve quadratic equation, we would put it firstly in the standard\general form! \(\Large ax^2+bx+c=0\)

That requires bringing back 4 to the left-hand side (with negative sign) and add (-11) to (-4), so we would get: \(x^2+2x-11-4=0\) and then:::
\[\LARGE\color{Coral}{ x^2+2x-15=0}\]

Answer 13

@zarkam21
so did you catch what I am saying?

Answer 14

Yes I understand

Answer 15

so you got which choice according to your understanding?

Answer 16

D?

Answer 17

Yes, You hit the right target!

That is the first step you would do to to start solving by a quadratic equation!