Question

help please

solve the differential equation

dy/dx = x^2y-y+x^2-1

Answer 1

@mathmale

Answer 2

@zepdrix

Answer 3

i was thinking of factoring iit
\[\frac{ dy }{ dx }= y(x^2-1)+(x^2-1)\]

Answer 4

Ooo nice :) I didn't see that.

Answer 5

\[dy/dx = (y+1)+(x^2-1)\]

Answer 6

Woops!

Answer 7

\[\large\rm \left[y\color{orangered}{(x^2-1)}+1\color{orangered}{(x^2-1)}\right]\quad=\quad \color{orangered}{(x^2-1)}[y+1]\]

Answer 8

No plus between the factors, ya?

Answer 9

oh crapt...yeh

Answer 10

so then hmm

Answer 11

Now sure?
Separate variables.
Get the y's on the left, leave the x's on the right.

Answer 12

\[|(y+1)|dy=(x^2-1)dx\]

Answer 13

Hmm I'm not sure what you did...
How did you move (y+1) to the left side..?

Answer 14

It was `multiplying` the x stuff,
so to move it to the left you must _________.

Answer 15

oh i did a mistake arghh


okay so the
1
_____ dy = (x^2-1) dx

(y+1)

Answer 16

Good

Answer 17

so then hmmm integerate

Answer 18

ln | y+1| = 1/3 x^3-1x

Answer 19

okay so then we put e