Question

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.

Which of these could be a step to prove that BC2 = AB2 + AC2?

By the cross product property, AB2 = BC multiplied by BD.
By the cross product property, AC2 = BC multiplied by BD.
By the cross product property, AC2 = BC multiplied by AD.
By the cross product property, AB2 = BC multiplied by AD.

Im thinking the answer is maybe A or C but I'm not sure. Please someone help me. Thank you!

Answer 1

what do you think it is?

Answer 2

I think it's either A or C

Answer 3

hmmm im not sure

Answer 4

what do u think it is

Answer 5

im on a test about this rn sooooo im not that sure but maybe C

Answer 6

i'm sorry i'm back had to restart my computer

Answer 7

is this flvs?

Answer 8

what teacher do you have?

Answer 9

yeah i think its c or a

Answer 10

mrs lewis

Answer 11

it might be c

Answer 12

Use the figure below to answer the question that follows:


What must be given to prove that ΔBDF ~ ΔCAE?

∠GBH ≅ ∠ICH and ∠BFD ≅ ∠CEA
segment BH is congruent to segment CH and segment BG is congruent to segment CI
∠GBH ≅ ∠ICH and ∠BIG ≅ ∠CGJ
segment BH is congruent to segment CH and segment HG is congruent to segment HI

Answer 13

hope its right fingers crossed

Answer 14

can u guys help me on this last one

Answer 15

@leenathan ^

Answer 16

@Love_333